| https://leetcode.com/problems/the-number-of-employees-which-report-to-each-employee/description/ | Easy |
|---|
SELECT
m.employee_id,
m.name,
COUNT(e.employee_id) AS reports_count,
ROUND(AVG(e.age)) AS average_age
FROM Employees AS m
JOIN Employees AS e
ON e.reports_to = m.employee_id
GROUP BY m.employee_id, m.name
ORDER BY m.employee_id;