| https://leetcode.com/problems/minimum-cost-to-move-chips-to-the-same-position/ | Easy |
|---|
fun minCostToMoveChips(position: IntArray): Int {
var even = 0
var odd = 0
for (pos in position) {
if (pos % 2 == 0) even++ else odd++
}
return minOf(even, odd)
}